Solution Mixture Formula

**Formula:** (OV1)(OS1) + (OV2)(OS2) = (NV)(NS)

OV1= Old Volume 1

OS1 = Old Strength 1

OV2 = Old Volume 2

OS2 = Old Strength 2

NV = New Volume

NS = New Strength

Note: OV1, OS1, OV2, OS2 are initial solutions meaning the first ones given. This formula is to find the extra % or ml that made the final volume solution or final strength solution.

[EX] A solution of 500ml of a 25% was made. One of the initial solution was 200ml of a 10% mixed with a 300ml of another solution. What is the final strength of the other initial strength?

Step 1: Plug given information in the formula to get a clear view on what it is missing and asking:

(OV1)(OS1) + (OV2)(OS2) = (NV)(NS)

(200ml)(10%) + (300ml)(X) = (500ml)(25%) [As you can see OS2 is not given so we would plug X to solve]

Step 2: Categorize solutions to solve

Solution 1 Solution 2 Solution 3

10% in 200ml x % in 300ml = 25% in 500ml

Step 3: 10 x 200= 2000 300x 25 x 500= 12500

Step 4: 2000 + 300x = 12500

Step 5: 300x = 12500 - 2000 = 10500

Step 6: Divide both sides to isolate x

[300x / 300] [10500 / 300 = 35] Final answer: X = 35% is in 300ml of a solution